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-16v^2/16=-81/16
We move all terms to the left:
-16v^2/16-(-81/16)=0
We get rid of parentheses
-16v^2/16+81/16=0
We multiply all the terms by the denominator
-16v^2+81=0
a = -16; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·(-16)·81
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-16}=\frac{-72}{-32} =2+1/4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-16}=\frac{72}{-32} =-2+1/4 $
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